√1+x^3 =3 than find the value of x?
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Answer:
Given :
x – (1/x) = 3√3
Formula used :
a2 + (1/a)2 = [a - (1/a)]2 + 2
a3 – (1/a)3 = [a – (1/a)]3 + 3[a – (1/a)]
Calculations :
[x – (1/x)] = 3√3
So,
x2 + (1/x2) = (3√3)2 + 2
⇒ 29
√3[x2 + (1/x2)]. = 29√3
Now
x3 – (1/x)3 = (3√3)3 + 3(3√3)
⇒ 90√3
[x3 – (1/x)3] - √3[x2 + (1/x2)] = 90√3 – 29√3
⇒ 61√3
∴ 61√3
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