Question

1-(x-3)-[(x-2)-(x+2)]=0​

Answer 1

$\Large{\bf{\green{\mathcal{\dag{\underline{\underline{QuestioN}}}}}}}$

If 1 - (x -3) - [(x - 2) - (x + 2)] 0, then find the value of x.

$\Large{\bf{\green{\mathcal{\dag{\underline{\underline{AnsweR}}}}}}}$

x = 8

$\Large{\bf{\green{\mathcal{\dag{\underline{\underline{Steps\: for \:the\: suM}}}}}}}$

1 - x + 3 - [x - 2 - x - 2] = 0

- x + 4 - [0 - 4] = 0

- x + 4 - (- 4) = 0

- x + 4 + 4 = 0

- x + 8 = 0

- x = - 8

x = 8