Question

(1/x+3)-(x/x^2-9) =( 2/3-x)

Answer 1

Acc to the question, the given equation is (1/x+3)-(x/x^2-9) =( 2/3-x).

$\frac{1}{x+3}$ - $\frac{x}{x²-9}$ = $\frac{2}{3-x}$

or, $\frac{x-3-x}{x²-9}$ = $\frac{2}{3-x}$

or, $\frac{3}{9-x²}$ = $\frac{2}{3-x}$

or, $\frac{3}{(3-x)(3+x)}$ = $\frac{2}{3-x}$

or, $\frac{3}{3+x}$ = 2.

or, 3 = 6 + 2x

or, 2x = -3

or, x = -1.5 [Ans]