Question

1.x-3y+0=0;a=1,b=-3,c=-6​

Answer 1

Step-by-step explanation:

Given x=3y

⟹x−3y=0

⟹(1)x+(−3)y+0=0

This is in the form of ax+by+c=0

So a=1,b=−3,c=0

Thank You :)

Answer 2

Answer:

1.x-3y+0=0;a=1,b=-3,c=-6

a=1,b=-3,c=-6