Question

(1)x - 3y - 3 = 0 ; 3x - 9y - 2 = 0

(2) 2x + y = 5 ; 3x + 2y = 8

(3) 3x - 5y = 20 ; 6x - 10y = 40

(4) x - 3y - 7 = 0 ; 3x - 3y - 15 = 0

by elimination method only please solve it please. ​

Answer 1

Answer:

There is no solution - the lines are parallel

Step-by-step explanation:

I'm going to assume we're to solve this system of equations.

We have:

x

−

3

y

−

3

=

0

3

x

−

9

y

−

2

=

0

Note that if we multiply the first equation by 3, we have:

3

x

−

9

y

−

9

=

0

3

x

−

9

y

−

2

=

0

And so for any given

x

, say

x

=

0

, we're going to have different

y

values. In this case, the first equation gives

y

=

−

1

and the second gives

y

=

−

2

9

.

In short, we have 2 parallel lines that will never intersect:

graph{(x-3y-3)(3x-9y-2)=0}