Question

( 1+x) (48+x)=(13+x) (6+x)​

Answer 1

$( 1+x) (48+x)=(13+x) (6+x)$

$1(48 + x) + x(48 + x) = 13(6 + x) + x(6 + x)$

$48 + x + 48x + {x}^{2} = 108 + 13x + 6x + {x}^{2}$

${x}^{2} + 49x + 48 = {x}^{2} + 19x + 108$

$49x + 48 = 19x + 108$

$49x - 19x = 108 - 48$

$30x = 60$

$x = \frac{60}{30}$

$\boxed{ \boxed{x = 2}}$