1/x+5+3/12x+4=1/x+2
![\frac{1}{x + 5} + \frac{3}{12x + 4} = \frac{1}{x + 2} \frac{1}{x + 5} + \frac{3}{12x + 4} = \frac{1}{x + 2}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7Bx+%2B+5%7D++%2B++%5Cfrac%7B3%7D%7B12x+%2B+4%7D++%3D++%5Cfrac%7B1%7D%7Bx+%2B+2%7D+)
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eska answer upper paper me hai.
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