1. (x-5) = 3(2x-4) 2. 2y - 3 = 3y+4 3. 3t + 2 = 2 (t+3) 4. 4n +5 =2 (3p-4) 5. 2\3b-3=2b+3 plz help me guys try to write the steps also
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Total number of permutations possible with 26 alphabets where SUN, TEA, BOY and GIRL occurs always, N(ABCD) = (26 - 3 - 3 - 3 - 4 + 4)! = 17! We can apply the principle of Inclusion and Exclusion to calculate the number of possible pemutations where none of the given pattern occur
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plz type question properly
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