1/(x+a)+1/(x+b)=1/c;if sum of roots of given equation is zero,then find value of (a+b)?
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Step-by-step explanation:
The sum of roots of equation 1/(x+a)+1/(x+b)=1/c is zero find the product of roots of .... Draw the Graph of the Polynomial when roots of the polynomial is given . ... (i)If `(a^2-1)x^2+(a-1)x+a^2-4a+3=0` is an identity in x, then find the value of a .
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4c^2
Step-by-step explanation:
1/(x+a) + 1/(x+b) = 1/c/ moving LHS to a common denominator and cross-multiplying,
(x+a+x+b)*c = (x+a)*(x+b)
Expanding RHS and simplifying LHS
(2x+a+b)*c = x^2 + (a+b)*x + ab
Moving LHS to RHS
x^2 + (a+b-2c)*x + ab - ac - bc = 0
Sum of roots = -(a+b-2c)/1 = 0
(or) a + b - 2c = o
(or) a+ b = 2c
Therefore (a+b)^2 = (2c)^2 = 4c^2
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