Question

1∫ x/√a²-x² dx (a>1) ,Evaluate it.-1

Answer 1

Answer:

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Answer 2

Answer:

0

Step-by-step explanation:

In this question

We have been given that

$\int_{-1}^{1}\frac{x}{\sqrt(a^{2}- b^{2})}\times dx$

Let,  $f(x)$ = $\frac{x}{\sqrt(a^{2}- x^{2})}$

Let, x replaced by -x then

$f(-x)$ = $\frac{-x}{\sqrt(a^{2}- (-x)^{2})}$

$f(-x)$ = $\frac{-x}{\sqrt(a^{2}- x^{2})}$

f(-x) = -f(x)

Therefore, I = f(-x) + {-f(x)} = 0

So, $\int_{-1}^{1}\frac{x}{\sqrt(a^{2}- b^{2})}\times dx$ = 0

Hence, the value of this equation  $\int_{-1}^{1}\frac{x}{\sqrt(a^{2}- b^{2})}\times dx$ = 0