Question

1. X as Y and Z as his son and grandson. His present age is 1.5 times the
age of his son and grandson. 10 years ago his age was twice the age of
his son and grandson, the present age of the father and sum of age of
son and grand-son are............​

Answer 1

Step-by-step explanation:

First let's look at the solution:

Let the present age of son be x

Then father's present age is 4x

Now,

According to question,

That is 10 years ago,

4x- 10 = 10 (x- 10)

4x -10=10x-100

100–10=10x-4x

90=6x

x=90/6

x=15

therefore,

Father=4x

=4*15

=60 years old

………………………………….…………………

Explanation in detail:

In the first line of the question we see that the question is talking about present ages therefore to start this one off we need simple algebra.Suppose that the sons age was x . Therefore fathers age would be 4 times sons age that's 4x.

In the second phase it talks about past or simply 10 years before the present time,Here we need to make an idea that when we are talking about past our ages will be less than the present time.So,to get the age for past we need to subtract 10 years form present age in this scenario.Fathers age would be 4x-10 and son's age would be x-10.

Third step,We now that to get the answer we need to equate things right? So as indicated in the question in past that's 10 years before the father was 10 times older then his son.

So its simple

4x-10= 10 *(x-10)

And then we can easily get the solution.Thanks for reading!!!!

Answer 2

Answer:

present age is 1.5 time the age of his son and grand son 45