Question

(1/x^b+x^-c+1)+(1/x^c+x^-a+1)+(1/x^a+x^-b+1)=1 Find (a+b+c)​

Answer 1

Answer:

LHS=

(2x−1)(3x+1)

x+1

;RHS=

(2x−1)

A

+

(3x+1)

(B)

=

(2x−1)(3x+1)

A(3x+1)+B(2x−1)

LHS=RHS

x+1=A(3x+1)+B(2x−1)

keep x=5; we get

6=16A+9B

So, 16A+9B=6