Question

1 - x
If f(x) = x > 0, then the least value of
1 + x
f{f(x)} + f{f(1/x)} is.
Numeric Answer:​

Answer 1

Step-by-step explanation:

f(x)=

x−1

x+1

fof(x)=

f(x)−1

f(x)+1

=

x−1

x+1

−1

x−1

x+1

+1

=

x+1−x+1

x+1+x−1

=x

i)(fofof)(x)=f(fof(x))=f(x)=

x−1

x+1

ii)(fofofof)(x)=fof(fof(x))=fof(x)=x

How satisfied are you with the answer?