Question

1 - X whole cube + 3 x minus 4 whole cube + 3 - 2 X whole cube​

Answer 1

${(1 - x)}^{3} + {(3x - 4)}^{3} + {(3 - 2x)}^{3} ={18x}^{3} - {69x}^{2}+87x -36$

${(1 - x)}^{3} + {(3x - 4)}^{3} + {(3 - 2x)}^{3}$

1-x + 3x - 4 + 3 - 2x = 0

as we know that

if a + b + c = 0

then a^3 + b^3 + c^3 = 3abc

here a= 1-x

b = 3x-4

c = 3-2x

3abc = 3(1-x)(3x-4)(3-2x)

= 3(1-x)(-6x^2 + 17x -12)

= 3 ( 6x^3 - 23x^2 + 29x -12)

= 18x^3 - 69x^2 + 87x - 36