[1-(x×x)][1-(y×y)]+4xy
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Answered by
0
HEY BRO.. HERE'S YOUR ANSWER..
Calculate the product.
• (1-x²)×(1-y²)+4xy
Now multiple the parentheses.
• 1-y²-x²+x²y²+4xy
I HOPE YOU FIND IT HELPFUL.
YOUR CARING FRIEND.
#LB... :-)
Calculate the product.
• (1-x²)×(1-y²)+4xy
Now multiple the parentheses.
• 1-y²-x²+x²y²+4xy
I HOPE YOU FIND IT HELPFUL.
YOUR CARING FRIEND.
#LB... :-)
Answered by
0
Hey!
[1 - x^2]*[1 - y^2] + 4xy
on opening the brackets we have
[1 - y^2 - x^2 + (x^2)(y^2)] + 4xy
1 - (x^2)(y^2) - x^2 - y^2 + 4xy
[taking negative sign common]
1 - (x^2)(y^2) - [ x^2 + y^2 - 4xy]
1 - (x^2)(y^2) - [(x - y)^2]
1 - x^2 y^2 - (x - y)^2
This is the answer.
[1 - x^2]*[1 - y^2] + 4xy
on opening the brackets we have
[1 - y^2 - x^2 + (x^2)(y^2)] + 4xy
1 - (x^2)(y^2) - x^2 - y^2 + 4xy
[taking negative sign common]
1 - (x^2)(y^2) - [ x^2 + y^2 - 4xy]
1 - (x^2)(y^2) - [(x - y)^2]
1 - x^2 y^2 - (x - y)^2
This is the answer.
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