Math, asked by nmadhavi80, 6 months ago


1+x+√x+ x/
√x+√1+x

dx =​

Answers

Answered by tarracharan
2

{\large{\boxed{\sf{∫(1+x+\sqrt{x}+\frac{x}{\sqrt{x}}+\sqrt{1}+x).dx}}}}

= {\large{\boxed{\sf{∫(1+x+\sqrt{x}+\sqrt{x}+1+x).dx}}}}

= {\large{\boxed{\sf{∫(2+2x+2\sqrt{x}).dx}}}}

= {\large{\boxed{\sf{2∫(1+x+\sqrt{x}).dx}}}}

= {\large{\boxed{\sf{2[∫1.dx+∫x.dx+∫{x}^{\frac{1}{2}}.dx]}}}}

= {\large{\boxed{\sf{2[x+\frac{x²}{2}+\frac{{x}^{\frac{3}{2}}}{\frac{3}{2}}+c]}}}}

= {\large{\boxed{\red{\sf{\frac{6x+3x²+4\sqrt{x³}}{3}+c}}}}}

Kindly vote me❤

Sai Charan | Shikshak of the year

https://shikshak.brainly.in/nomination/sai-charan/

Similar questions