Question

1+x+x2=0 using quadratic equation formula​

Answer 1

$for \: \\ a {x}^{2} + bx + c = 0 \\ \\ x = \frac{ - b + | \sqrt{ {b}^{2} - 4ac} | }{2a} \\ \\ now \\ \\ {x}^{2} + x + 1 = 0 \\ \\ x = \frac{ - 1 + i\sqrt{3} }{2} \\ \\ x = \frac{ - 1 - i \sqrt{3} }{2} \\ \\ {i}^{2} = - 1$

hope it helps