Question

1/x+y = 1/x + 1/y then find the value of ( x/y)^6 + (x/y)^3​

Answer 1

Answer:

0

Step-by-step explanation:

given that 1/x+y=1/x+1/y;

1/x+y=x+y/xy;

(x+y)^2=xy;

x^2+y^2+2xy=xy;

x^2+y^2-xy=0 (let this be eqn 1)

(x/y)^6+(x/y)^3=(x^6+x^3*y^3)/y^6

=[x^3(x^3+y^3)]/y^6

=[x^3{(x+y)(x^2-xy+y^2)}]/y^6

=[x^3{(X+y)*(0)}]/y^6

=0