Question

1) (x Y ² + x) dx + (yx^2+y) dy
=0​

Answer 1

Step-by-step explanation:

$d {x}^{2} {y }^{2} + d {x}^{2} + d {x}^{2} {y}^{2} + d {y}^{2} \\ \\ \\ \\ d {x}^{2} ( {y}^{2} + 1) + d {y}^{2} ( {x}^{2} + 1)$