Question

(1) x+y=5, 2x+2y= 10
(ii) x-y8,
3x - 3y = 16
(iii) 2x+y-6=0, 4x - 2y-4=0
(iv) 2x - 2y -2=0 ,4x - 4y - 5 = 0​

Answer 1

Explain the Question properly

Answer 2

Answer:

1. 0

2.

3. 32

4. -2

I must say the questions are really tricky

Step-by-step explanation:

Using elimination method:

1. x+y=5    eqn i

2x+2y= 10  eqn ii

Let use y

x+y=5 * 2

2x+2y=10 *1

Since the coefficient of y are different we multiply

2x+2y=10

2x+2y=10

Since we can eliminate everything our answer will be= 0

2. x-8y=0  eqn i

    3x-3y=16  eqn ii

Let use y

Since the coefficient of y are not the same we multiply

x-8y=0 *3

3x-3y=16  * 8

3x-24y=0

24x-24y=128

-21x=128

x=-6 2/21

Sorry don't really get these question

3. 2x+y=6  eqn i

   4x-2y=4  eqn ii

2x+y=6  * 4

4x-2y=4  * 2

8x+4y=24

8x-4y=8

=32

4. 2x-2y=2

    4x-4y=5

2x-2y=2 * 4

4x-4y=5  * 2

8x-8y=8

8x-8y=10

= -2