Math, asked by asishrocky99, 1 year ago

(1+x/y+x^2/y^2) (1-x/y+x^2/y^2) (1-x^2/y^2)​

Answers

Answered by choco94
2
(y2+xy+x2/y2)(y2-xy+x2/y2)(y2-x2/y2)

(x2+y2/y2)(x2-y2/y2)(y2-x2/y2)

(x2+y2)(x2-y2)(y2-x2)/y6

x4-x2y2+x2y2-y4+x2y2-x4-y4-x2y2/y6

-2y4/y6= -2/y2 ans

Answered by tiwaripoonam9032
0

Answer:

(y2+xy+x2/y2)(y2-xy+x2/y2)(y2-x2/y2)

(x2+y2/y2)(x2-y2/y2)(y2-x2/y2)

(x2+y2)(x2-y2)(y2-x2)/y6

x4-x2y2+x2y2-y4+x2y2-x4-y4-x2y2/y6

-2y4/y6= -2/y2 ans

Step-by-step explanation:

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