Question

(1) x² - 11x - 42

2) x⁴ - y⁴

Answer 1

Holla ^_^


☸ Required Answer is ⬇⬇ ⬇⬇ ⬇


⭕ 1). x² - 11x - 42

=> x² + 3x - 14x- 42

=> x (x+3) -14 (x +3)

=> (x+3) (x-14)

x+3 = 0. or x-14 =0

x = -3. or. x = 14


2). x⁴ - y⁴

by using a² - b² identity

=>. (x² + y²) (x² -y²)

=> (x² + y²) (x+y) (x-y)


Vielen Dank ♥

Answer 2

heya bro... here is your answer

1) x² -11x - 42

x² +14x - 3x -42

x(x+14) -3(x+14)

(x-3) (x+14)

=> x =3 and x = -14

2) x⁴ -y⁴

(x²)² - (y²)²

(x² + y²) (x² - y²)

(x² + y²) (x+y) (x-y)

$hope \: it \: hlps \: u \: bro \:$