Question

1) x² + 3x -5 = (x + 9)^2​

Answer 1

Answer:

 - $5\frac{11}{15}$

Step-by-step explanation:

(a ± b)² = a² ± 2ab + b²

~~~~~~~~~~~

x² + 3x - 5 = (x + 9)²

x² + 3x - 5 = x² + 18x + 81

15x = - 86

x = - $\frac{86}{15}$

x = - $5\frac{11}{15}$

Answer 2

simplify LHS and RHS and then for linear equation and solve to find x

Here is the solution

x²+3x-5=(x+9)² (a+b)²=a²+b²+2ab

x²+3x-5=x²+81+18x on cancelling x² on both lhs and rhs since the have same sign

3x-5=81+18x on transposing

-5-81=18x-3x

-86=15x

x=-86/15

Hope it helps

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