Question

(1) (x2 - 4xy + y) (x-2) : x = 3, y = 2
ii) (7xy - 32) (x + y + 7); = 1, y = 1, z​

Answer 1

Answer:

1 (X2-4xy +y) (x-2):x=3, y=2

Step-by-step explanation:

put value of x=3 and y=2 we get

(3*2-4*2*3+2) (3-2)

(6-24+2) (1)

(6-22)

-16

2) (7xy-32) (x+y+7)

putting x=3and y=2, we get

(7*3*2 -32) (3+2+7)

(42-32)(12)

10*12

120