Question

1. x2 - 8x + 16 = 0​

Answer 1

Step-by-step explanation:

$\huge \mathfrak{ \underline{ \red{ \: solution}}} : -$

$\sf \to \: x^2-8x+16=0 \\ \\ </p><p> \sf \to \: x^2-4x-4x+16=0 \\ \\ </p><p> \sf \to \: x(x-4)-4(x-4)=0 \\ \\ </p><p> \sf \to \: (x-4)(x-4) =0 \\ \\ \sf \to \: \red{</p><p>x=4}$

$\huge \mathfrak{ \underline{ \orange{ \: verification}}} : -$

$\sf \to \: {x}^{2} - 8x + 16 = 0 \\ \\ \sf \to \: \: {4}^{2} -8 \times 4 + 16 = 0 \\ \\ \sf \to \: \: \: 16 - 32 + 16 = 0 \\ \\ \sf \to \: \:32 - 32 = 0 \\ \\ \sf \to \: \:0 = 0$

$\huge \mathfrak{ \underline{ \pink{ \: hence \: verified}}} : -$

$\huge \mathfrak{ \underline{ \purple{ \: additional \: information}}} : -$

• A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared.

• The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable

Answer 2

$\underline\mathfrak{\pink{ \: Solution :- }}$

$\to {x}^{2} - 8x + 16 = 0$

$\to \: ( {x}^{2} - 4x) - (4x + 16) = 0$

$\to \: (x - 4) - (x + 4) = 0$

$\red{ \to \: x + 4 = 0 }$

$\boxed{ \pink{x = y}}$

$\boxed{ \pink{ \cancel{x = 4}}}$

$\: \underline\mathfrak{\blue{ \: Verification :- }}$

$\to {(4)}^{2} - 8(4) + 16 = \red{0}$

$\to {x}^{2} - 8x + 16 = \red{0}$

$\to \: 16 - 32 + 16 = \red{0}$

$\to \: 32 - 32 = \red{0}$

$\huge \boxed{ \green{0 = 0}}$