Question

(1) (x2 – x)2 -8 (x2 - x) + 12​

Answer 1

Answer:

(x²-x)²-8(x²-x)+12

= (x-3)(x+2)(x-2)(x+1)

Step-by-step explanation:

(x²-x)²-8(x²-x)+12

Let x²-x = a, the expression becomes

a²-8a+12

Splitting the middle term, we get

= a²-6a-2a+12

= a(a-6)-2(a-6)

= (a-6)(a-2)

= (x²-x-6)(x²-x-2)

= (x²-3x+2x-6)(x²-2x+x-2)

= [x(x-3)+2(x-3)][x(x-2)+1(x-2)]

=(x-3)(x+2)(x-2)(x+1)

Therefore,

(x²-x)²-8(x²-x)+12

= (x-3)(x+2)(x-2)(x+1)

•••♪

Answer 2

Answer:

(1)(x2-x)2-8(x2-x)+12

(x2-x)2-8(x2-x)+12

4x-2x-16x+8x+12

2x-8x+12

-6x+12=0

-6x=-12

x=-12/-6

x=2