Question

1.
x² + y² +6x+2y=0,
(x+y+8=0
Answer ?

Answer 1

Answer:

0

Step-by-step explanation:

= x२+y२+6x+2y= x+y+8= 0

= x२+y२+6x+2y

= x+y(x+y+6+2)=0

= x+y(x+y+8)=0

= x+y(0)=0

= x+y=0

Answer 2

Answer:

The result is $x+y=0$

Step-by-step explanation:

It is given that $x+y+8=0$. --(1)

Using this, we need to solve $x^{2} + y^{2} +6x+2y=0$

Now,

$x^{2} + y^{2} +6x+2y=0$

It can be factorized as $(x+y) (x+y+6+2)=0$

$(x+y) (x+y+8)=0$

Using (1), we get

$(x+y) (0)=0$

Hence, the result is $x+y=0$

#SPJ2