1) x⁴- 7 x² + 12
2) a⁶ + 3a³b³-40b⁶
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Answer:
1) x² - 7x² + 12
⇒x⁴ - (4 + 3) x² + 12
⇒x⁴ - 4x² - 3x² + 12
⇒x² (x²- 4) -3 ( x² - 4)
⇒(x²- 4) (x²- 3)
⇒{(x)²- (2)²} (x² - 3)
⇒(x + 2) (x - 2) (x²-3 )
2) a² + 3a³b³ - 40b ⁶
⇒a⁶ + 8a³b³ - 5a³b³ - 40b⁶
⇒a³ ( a³+ 8b³) - 5b³(a³ + 8b³)
⇒(a³ + 8b³ ) (a³-5b³)
⇒{(a)³ + (2b)³} (a³-5b³)
⇒(a+ 2b) {a²-a.2b + ( 2b)² } (a³ - 5b³)
⇒(a + 2b)(a² - 2ab + 4b²)(a³ -5b³)
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Explanation:
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