Question

1. Xml of H, gas effuses through a hole in a container
in 5 sec. The time taken for the effusion of same
volume of gas specified below under identical
conditions is
1) 10 sec, He
2) 20 sec, 0,
3) 25 sec, CO
4)55sec, CO2
Explain ​

Answer 1

Answers

Answer is option 2

Explanation:

Molecular mass of Hydrogen is 2 and that of oxygen is 32

We know that, the time taken for effusion is indirectly proportional to the Square root of molecular mass

rate of effusion \alpha 1 / square root of molecular mass

rate of H2 / rate of O2 = Square root of 32/ Square root of 2

rate of H2 / rate of O2 = 5.66 / 1.41 = 4

rate of O2 = 4 times the rate of H2

= > 4 * 5 = 20 seconds

It is given that oxygen takes 20 seconds for effusion. Hence verfied