Question

1. y = x2 - 6x - 3
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Answer 1

y=(x+3) square −12

I think it helps you ✳️⚡

Answer 2

Question

y=x²-6x-3. Solve the value of y.

$\huge \bf \blue \curvearrowleft \green{Answer}$

$\tt{ \twoheadrightarrow \: y = x {}^{2} - 6x - 3 }$

Here, the first term is x²

the second or middle term is 6x

the constant is 3

Firstly let us multiply the coefficient of the first term with the constant.

1×(-3) = -3.

Now we must find the factors of (-3) whose sum will be equal to the middle term. The factors are below

-3 × 1 = -3 and -1×3 = -3

It is observe that in such condition, no factors can be found.

Therefore, the given equation is not proper.