Math, asked by imsultana74, 6 months ago

1+y³÷1+y divide
please give the correct answer​

Answers

Answered by Anonymous
1

\huge\mathfrak\red{Here's\:your\:answer}

1+y³ / 1+y

Taking y common

y(1+y²)/ y(1)

or (1+y²) / 1

Taking 1 common

1(y²) / 1

or y² is your answer

\bf\mathtt\red{Other\:process}

1+y³ / 1+y

Taking y common

y(1+y²)/ y(1)

or (1+y²) / 1

or Putting formula of (a+b)²

y²+1+2y /1

Taking 1 common

1(y²+2y)/1

or y²+2y (Ans)

Answered by kirtikagawanday
0

Answer:

1³+y³ = (1+y)(1²-y+y²)

now ,  (1+y³)/(1+y) = (1+y)(1²-y+y²)/(1+y)

= (1-y+y²)

Step-by-step explanation:

HOPE IT WILL HELP U

Similar questions