Question

1. यदि बहुपद fx= 5x + 13x + k का एक शून्यक दूसरे का व्युत्क्रम हो,
तोk का मान होगा-​

Answer 1

Answer:

1

Step-by-step explanation:

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Answer 2

The value of k is 5.

Step-by-step explanation:

Note: The given polynomial is incorrect because it is not a quadratic.

Consider the given polynomial is

$f(x)=5x^2+13x+k$

It given that one zero inverse of other.

Let the two zeroes are x and 1/x.

If a polynomial is $f(x)=ax^2+bx+c$, then

Product of zeroes = c/a

In the given polynomial, a=5,b=13 and c=k.

Product of zeroes is

$x\times \dfrac{1}{x}=\dfrac{k}{5}$

$1=\dfrac{k}{5}$

Therefore, the value of k is 5.

#Learn more

If one zero of the polynomial (k+1)x^2 - 5x +5 is multiplicative inverse of the other then find the zeroes of kx^2 -3kx +9.

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