Question

1 year ago father was 8 times as old as his son's age now his age is the square of his son's age find their present ages ​

Answer 1

Answer:

. Now son=x

father, x^2

lyr ago, Son=x-l

father=X^2-l

X^2-l=8(X-I)

x^2-1=8x-8

x^2-8x+7=0

(x-7) (x-l)=0

x =7 or I

present age of son=7

father 7^2 = 49