Math, asked by parthamandal42782, 1 year ago

1 year ago Rohini was four times as old as her daughter Sakshi. Six years hence Rohini's kids exceed her daughters age by 9 years. The ratio of the present ages of Rohini and her daughter is ?​

Answers

Answered by jeslinbenittaj
0

Answer:

The ratio of present ages of Rohini and her daughter is 13:4

Step-by-step explanation:

Let A be present age of Rohini

B be present age of her daughter

*See attachment*

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Answered by psupriya789
0

Let Nikitha's age 1 year ago = x

Then Jaya's age 1 year ago = 4x

After 6 years their ages are = (4x + 7), ( x + 7)

So,

(4x + 7) - (x + 7) = 9

=> 4x + 7 - x - 7 = 9

=> 3x = 9

=> x = 3

Present age of Jaya = (12+1) years = 13 years

Present age of Nikitha = (3+1) years = 4 years

Ratio of their ages = 13 : 4

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