Question

1) You play a game with 0.3 as the probability of winning. What is the probability that you win 4 or more games out of 10?
(Hint :Round-off to three decimal places)​

Answer 1

Answer:

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Answer 2

Answer:

The probability that you win 4 or more games out of 10=0.07

Step-by-step explanation:

P(A)=PROBABILITY OF WINNING=0.3

P(B)=PROBABILITY OF LOSING

P(A)+P(B)=1

0.3+P(B)=1

P(B)=1-0.3

      =0.7

Probability of winning= $P(A)=\frac{4}{10} *\frac{5}{10} *\frac{6}{10} *\frac{7}{10} *\frac{8}{10} *\frac{9}{10}* \frac{10}{10} = 0.07$

0R

Another method

$P(K \ge 4) = \sum_{k=4}^{10} \binom{10}{k} \left (\frac12\right)^k \left ( \frac{1}{2}\right )^{10-k} \\\P(K \ge 4) = \sum_{k=4}^{10} \binom{10}{k} \left (\frac12\right)^4 \left ( \frac{1}{2}\right )^{6} \\\\\=.07$