Question

1 ZBAC = 70° and ZDAC = 40°. then find ZBCD
ii. ZBAC - 60° and ZBCA -60°, then find LADC​

Answer 1

Hey mate,..

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1 ZBAC = 70° and ZDAC = 40°. then find ZBCD

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∠AOB=∠COD=105 ∘

(Vertically Opposite Angles)

In triangle AOB,

∠BAO+∠AOB+∠OBA=180 ∘

30∘ +105 ∘ +∠OBA = 180∘

∠OBA=45 ∘ AB and CD are parallel

∴∠OBA=∠CDO=45∘ (Alternate Interior angles)

Hope it helps...

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