Question

10^0.48=x , 10^0.36=y ,x^p=y^2 find p​​

Answer 1

Answer:

$\huge{\mathcal{\underline{\green{SOLUTION}}}}$

$\displaystyle \: {10}^{0.48} = \: x \: , {10}^{0.36} =y$

$\displaystyle \: logx \: = 0.48 \: log10 = 0.48$

$\displaystyle \: logy \: = 0.36 \: log10 = 0.36$

Now

$\displaystyle \: {x}^{p} = {y}^{2}$

$\displaystyle \: p \: logx \: = \: 2 \: logy$

$\displaystyle \: p \: \times 0.48 = 2 \times 0.36$

$\displaystyle \: p \: = \frac{0.72}{0.48}$

$\displaystyle \: p \: = \frac{3}{2}$