Question

-
10.0 mL of a solution contains 5.6 x 10-4 g of sodium ions. The concentration in
ppm
is
a) 28 ppm
b)
c) 5.6 ppm
56 ppm​

Answer 1

Answer:

The answer would be c plz check it out may be wrong

THANKS

fell free to ask other questions

Answer 2

The answer is 56 ppm.

Explanation:

One ppm (parts per million) is defined as the ratio of one milligram of solute and one liter of solution or one microgram of solute per milliliter of solution.

$1 ppm = \frac{1 mg}{1L}$ or $1ppm = \frac{1micro g}{1mL}$

Given, the mass of solute, sodium ions $= 5.6\times 10^{-4} g$

and Volume of solution = 10 mL

Since the mass of solute is given in grams, we need to convert it into micrograms, to use volume in terms of mL.

Thus, the mass of solute $= 5.6 \times 10^{-4} g \times \frac{10^{6} micro g}{1 g}$

$= 5.6 \times 10^{2} micro grams$

Hence, concentration in ppm $= \frac{5.6 \times 10^2}{10}$ $= \frac{560}{10}$$= 56$

Hence, the answer is 56 ppm.