Question

(10-0)x(10-1)x(10-2)x(10-3)x................=?

Answer 1

Solution :

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Given :

To find the value of :

10 × (10 - 1) × (10 - 2) ....∞

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The series goes from 10 to ∞,.

The common difference of each number in the series is -1,

Hence,.

The series shall go :  10 × (10 - 1) × (10 - 2) × (10 - 3) × (10 - 4) ..(10 - 8) × (10 - 9) × (10 - 10) × (10 - 11) ...∞

⇒ 10 × 9 × 8 × 7 × 6...2 × 1 × 0 × (-1) × (-2) ...∞

We know that 0 × any integer is 0,.

Hence,

⇒ 0

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                                      Hope it Helps !!