Chemistry, asked by Darknight8642, 1 year ago

10.0g of iron(ii) ammonium sulphate crystals were made up to 250cm3 of acidified aqueous solution. 25.0cm3 of this solution required 21.25cm3 of

Answers

Answered by anuragojha47
0

Explanation:

3.00 g of a lawn sand containing an iron (II) salt was shaken with dilute H2SO4. The resulting solution required 25.00 cm3 of 0.0200 mol dm-3 potassium manganate (VII) to oxidise the Fe2+ ions in the solution to Fe3+ ions. Use this to calculate the percentage by mass of Fe2+ ions in this sample of lawn sand.

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