Chemistry, asked by Darknight8642, 11 months ago

10.0g of iron(ii) ammonium sulphate crystals were made up to 250cm3 of acidified aqueous solution. 25.0cm3 of this solution required 21.25cm3 of

Answers

Answered by anuragojha47
0

Explanation:

3.00 g of a lawn sand containing an iron (II) salt was shaken with dilute H2SO4. The resulting solution required 25.00 cm3 of 0.0200 mol dm-3 potassium manganate (VII) to oxidise the Fe2+ ions in the solution to Fe3+ ions. Use this to calculate the percentage by mass of Fe2+ ions in this sample of lawn sand.

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