Question

10.0ml mixture of methane and ethylene was exploded with 30mlof oxygen

Answer 1

Answer:

Explanation:Volume of the mixture = 10ml

Volume of excess of oxygen = 30 ml

Volume of the mixture after cooling = 21 ml

Volume after treatment with KOH = 7 ml

To Find :

The amount of methane and ethylene in the mixture

Solution :

Let the amount of methane (CH₄) = x ml

The amount of ethylene(C₂H₄) = (10-x) ml

The following reactions took place during the process

            

The volume of CO₂ absorbed by KOH = 21 - 7 = 14 ml

            

            

Volume of CH₄ = 6 ml

      Volume of C₂H₄ = (10-6) = 4 ml