Question

10.
1 mole of real gas (a = 1.4) oocupies a volume of
0.1 L at 300K then the pressure of gas will be :-
(1) 2460 atm
(2) 2320 atm
(3) 106 atm
(4) 212 atm​

Answer 1

Explanation:

p*v = n*R*t

p = 1*8.314*300/(0.1*10^-3)

= 2494.2*10^4 = 249 atm