10.
1 mole of real gas (a = 1.4) oocupies a volume of
0.1 L at 300K then the pressure of gas will be :-
(1) 2460 atm
(2) 2320 atm
(3) 106 atm
(4) 212 atm
Answers
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Explanation:
p*v = n*R*t
p = 1*8.314*300/(0.1*10^-3)
= 2494.2*10^4 = 249 atm
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