Question

10,11,12,13,14 ppppppplease do this aall

and please do not type annoying massages

Answer 1

Answer:

(i)  12 and 14 have the same image hence f1 is many-one,

    also domain=codomain  ∴f is not onto.

(ii) Every element has the same image 1 so f2 is a constant function. It is not onto.

(iii) Every element has a unique image and domain=codomain hence f3 is one-one and onto.

hope it helps you