10,13, 16,........... for given AP check whether 162 is term of an AP
or not?
Answers
Answered by
1
Answer:
No 162 is not a term of this AP
Answered by
0
ANSWER
Given series is 1,4,7,10,13,16,19,22,25,....
Since, 4−1=7−4=10−7,.....
i.e 3=3=3,......
Given the common difference is 3.
Therefore, the given sequence is an AP.
Hence, option A is correct
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