10^16 electrons each having charge of 1.6×10−19C ,pass from a point A towards anotherpoint B in 0.1 sec. Calculate the current in ampere and give its direction
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Charge the electron is given as e = 16×10power9c
Number of electron is given as n = 10power20
and this time taken is given from point A towards another point B as it.
= 0.15
Then,
the current will be given as
(next solution is in attachment)
160A is Answer..
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