Question

10^18 electrons move from point A to point B inside a metal wire in 4 seconds. What is the current passing through the wire?

Those who will tell the correct and was marked as a Brain list​

Answer 1

i current =Ne-×Q/T

charge of 1 electron =1.602×10^-19×10^18/4

1.602×10^-1/4=0.1602/4=0.04005A

Answer 2

GIVEN :–

• 10¹⁸ electrons move from point A to point B inside a metal wire in 4 seconds.

TO FIND :–

• Current passing through the wire = ?

SOLUTION :–

▪︎ CURRENT :–

Rate of flow of charge is called Current .

☞ $\: \: \: \: \: \large{ \red{ \boxed{ \bold{ I = \dfrac{Q}{t} }}}}$

☞ S.I. unit of current is Ampere .

• Here –

$\\ \: \: \: { \huge{.}} \: \: \: \: { \bold{ I = current }}$

$\\ \: \: \: { \huge{.}} \: \: \: \: { \bold{ Q = charge }}$

$\\ \: \: \: { \huge{.}} \: \: \: \: { \bold{ t = time }}$

▪︎ Now let's calculate 'charge' –

• We know that –

$\\ \: \: \: \longrightarrow \: \: \: { \red{ \boxed{ \bold{ Q = \: ne }}}}$

• Here –

$\\ \: \: \: { \huge{.}} \: \: \: \: { \bold{ n = number \: \: of \: \: electrons }}$

$\\ \: \: \: { \huge{.}} \: \: \: \: { \bold{ Q = charge }}$

$\\ \: \: \: { \huge{.}} \: \: \: \: { \bold{ e = charge \: \: on \: \: electron }}$

$\\ \implies { \bold{Q = {10}^{18} \times 1.6 \times {10}^{ - 19} \: \: [ \: \because \: e=1.6 \times {10}^{ - 19} ]}}$

$\\ \implies { \bold{Q = 1.6 \times {10}^{ - 1} \: \:}}$

$\\ \implies \large{ \pink{ \boxed{ \bold{Q = 0. 16 \: c \: \:}}}}$

• Now current –

$\\ \implies { \bold{ I = \dfrac{Q}{t} }}$

$\\ \implies { \bold{ I = \dfrac{0.16}{4} }}$

$\\ \implies \large { \pink{ \boxed{ \bold{ I = 0.4 \: \: \: A }}}}$

$\\ \rule {220}{2}$