Question

10^19
electrons flows in a wire
30 minites what will be
current
?​

Answer 1

$\huge\star{\green{\underline{\mathfrak{Answer :-}}}}$

Given:

• Electrons flowing in the wire = $\tt{10^{19}}$
• Time = 30 minutes

To find:

• Current or I

Solution:

Firstly, we will have to find the Charge.

We know that,

$\boxed{\red{\tt{Q=\pm ne}}}$

Using this formula,

$\leadsto\tt{Q = 10^{19} \times (- 1.6 \times 10^{-19} )}$

$\leadsto\tt{Q = 10^{19} \times - 1.6 \times \dfrac{1}{10^{19}}}$

$\huge\leadsto\tt{\underline{\orange{- 1.6\:Coulomb}}}$

Now, finding the current.

We know that,

$\boxed{\red{\tt{I = \dfrac{Q}{t}}}}$

Using the formula,

$\leadsto\tt{I =\dfrac{- 1.6}{30\times 60}}$

$\leadsto\tt{I=\dfrac{-16}{30\times60\times10}}$

$\leadsto\tt{I=\dfrac{-1}{1225}}$

$\leadsto\tt{I=- 0.000816\:A}$

$\huge\leadsto{\boxed{\purple{\underline{\tt{I=-8.16\times10^{-4}\:Ampere}}}}}$

$\rule{200}4$

Answer 2

Question

10^19 electrons flows in a wire 30 minites what will be current ?

Solution

Given

• No.of Electrons (n) = 10^19

• Time taken (t) = 30 min

Firstly,we would need to the find the charge flowing through the conductor

Quantization of Charge

Any particle would have a charge which is an integral multiple of a charge of an electron.

$\sf \: Q \: = \pm \: ne$

Here,

Q is the charge of Particle

n is the no.of electrons

e is the charge of an electron

Charge of an electron :

$\sf \: \: e = - 1.6 \times {10}^{ - 19}$

Putting the values,

$\longrightarrow \: \sf \: Q = - \: (10 {}^{19}) \times 1.6 \times {10}^{19} \\ \\ \longrightarrow \: \boxed{ \boxed { \sf \: Q = - 1.6 \: C}}$

Using the definition of electric current

$\sf \: l = \dfrac{Q}{t}$

• Time taken = 30 × 60 = 1800

$\longrightarrow \: \sf \: l = - \dfrac{1.6}{1800} \\ \\ \longrightarrow \: \sf \: l = - \frac{16}{18} \times {10}^{ - 3} \\ \\ \longrightarrow \: \boxed{\boxed{ \sf \: l = - 0.089 \times {10}^{ - 3} \ Amperes}}$