Question

10-2 (1+4x) <20,X=z​

Answer 1

$\rm{10-2 (1+4x) <20, \: \: x \in Z } \\ \\\huge = > 10 - 2 - 8x < 20 \\ \\ \huge = > (10 - 2) - 8x < 20 \\ \\ \huge = > 8 - 8x < 20 \\ \\ \huge = > 8(1 - x) < 20 \\ \\\huge = > \frac{8(1 - x)}{8} < \frac{20}{8} \\ \\\huge = > 1 - x < \frac{20}{8} \\ \\\huge = > 1 - x - 1 < \frac{20}{8} - 1 \\ \\\huge = > \: \: \: \: \: \: - x < \frac{20 - 8}{8} \\ \\\huge = > \: \: \: \: \: \: - x < \frac{16}{8} \\ \\\huge = > \: \: \: \: \: \: - x < 2 \\ \\ \huge = > \: \: \: \: \: \: \frac{ - x}{ - 1} < \frac{2}{ - 1} \\ \\ \huge = > \: \: \: \: \: \: x < - 2$