Math, asked by mohammedhazeem, 6 months ago

(10+2)²-(10-2)²=
(x+y)²-(x-y)²=
(10+0.6)²-(10-0.06)²=​

Answers

Answered by gauravshukla6664
0

Answer:

(10+2)^2-(10-2)^2

12^2-8^2=80

(x+y)^2-(x-y)^2=

(x^2+y^2+2xy)-(x^2+y^2-2xy)

x^2+y^2+2xy-x^2-y^2+2xy

= 4xy

(10+0.6)^2-(10-0.6)^2=

(10.6)^2-(9.4)^2

102.36-88.36

14

Answered by akkant1978
0

Answer:

=(a+b) ^2 - (a-b) ^2

=(a^2+b^2+2ab) -(a^2+b^2-2ab)

=(10^2+2^2+2*10*2) -(10^2+2^2-2*10*2)

=(100+4+40) - (100+4-40)

=(144-94)

=144-94

=50

2. =(x^2+y^2+2*x*y) - (x^2+y^2-2*x*y)

= (x^2+y^2+2xy) -(x^2+y^2-2xy)

= x^2+y^2+2xy - x^2-y^2+2xy

=4xy

3. answer=102.3636

Similar questions