10
2.
4. A block (mass = M kg) is placed on a rough inclined
plane. A force Fis applied parallel to the inclined (as
shown in figure) such that it just starts moving upward.
The value of Fis
FM
(1) Mg sin 8-uMg cos 0 (2) Mg sin e + Mg cos 0
(3) Mg sin e
(4) uMg cos e
Figum
2
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Answer:
Given that r= radius= 5 cm
Total surface area=165
Explanation:
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